K 折交叉验证:无数据泄漏地划分
您将使用 cross_val_score 实现 5 折 CV,理解为什么测试折在训练期间从未被使用,并解读 CV 分数的均值和标准差。
K 折交叉验证:无数据泄漏地划分 是 CoddyKit 上的免费 Machine Learning Academy 课时。 这是第 1 节课,共 4 节。 你可以在下方免费阅读本课时的完整内容 — 然后在浏览器中使用内置代码编辑器和全天候 AI 导师进行实践。 这是 Machine Learning Academy 学习路径的一部分,你的进度在网页和 CoddyKit 应用中同步。 Machine Learning Academy 课程共包含 4 节课。
本课时的部分内容尚未翻译,以英文显示。
Why a Single Train-Test Split Is Risky
When you evaluate a model on a single held-out test set, the result depends heavily on which examples happened to end up in the test set. With a small dataset, 80 test examples might be unusually easy or hard, making your accuracy estimate misleading. K-Fold Cross-Validation solves this by averaging accuracy across multiple test folds, giving a more reliable estimate of how the model will perform on new data. It also uses the data more efficiently — every example is used for both training and testing across different folds.
How K-Fold CV Works Step by Step
K-Fold CV splits the dataset into k equally sized parts called folds. In each of k rounds, one fold is used as the test fold and the remaining k-1 folds form the training set. The model is trained from scratch on the training folds and evaluated on the test fold. This repeats until every fold has served as the test fold exactly once. The final performance estimate is the mean (and standard deviation) of the k scores. Common values: k=5 or k=10.
cross_val_score: One-Line Cross-Validation
scikit-learn's cross_val_score handles the entire K-Fold loop: it creates the folds, trains the model on each training portion, evaluates on the test fold, and returns an array of scores. The cv parameter sets the number of folds. The scoring parameter specifies the metric. You can also pass n_jobs=-1 to train all folds in parallel, dramatically reducing wall-clock time on multi-core machines.
from sklearn.linear_model import LogisticRegression
from sklearn.datasets import load_breast_cancer
from sklearn.model_selection import cross_val_score
from sklearn.preprocessing import StandardScaler
from sklearn.pipeline import make_pipeline
import numpy as np
X, y = load_breast_cancer(return_X_y=True)
model = make_pipeline(StandardScaler(), LogisticRegression(max_iter=1000))
scores = cross_val_score(model, X, y, cv=5, scoring='accuracy', n_jobs=-1)
print('Fold scores:', np.round(scores, 4))
print('Mean:', round(scores.mean(), 4), 'Std:', round(scores.std(), 4))The Test Fold Is Never Seen During Training
The critical rule of K-Fold CV is that the test fold must never influence the model or any preprocessing step. This means the scaler must be fitted only on the training folds and then applied to the test fold — never fitted on the combined data. Using a Pipeline with cross_val_score automatically enforces this: scikit-learn calls fit on the training portion of the pipeline and predict on the test portion inside each fold, preventing any leakage.
# WRONG: fitting scaler on all data before CV causes leakage
from sklearn.preprocessing import StandardScaler
from sklearn.linear_model import LogisticRegression
from sklearn.model_selection import cross_val_score
from sklearn.datasets import load_breast_cancer
X, y = load_breast_cancer(return_X_y=True)
scaler = StandardScaler()
X_scaled = scaler.fit_transform(X) # leaks test fold statistics!
wrong_score = cross_val_score(LogisticRegression(max_iter=1000), X_scaled, y, cv=5).mean()
# CORRECT: Pipeline ensures scaler is fitted only on training folds
from sklearn.pipeline import make_pipeline
correct_score = cross_val_score(make_pipeline(StandardScaler(), LogisticRegression(max_iter=1000)), X, y, cv=5).mean()
print('Wrong (leaky):', round(wrong_score, 4))
print('Correct (no leak):', round(correct_score, 4))Setting the Random Seed for Reproducibility
By default, KFold does not shuffle the data and always creates the same splits for the same dataset, making results reproducible. If you set shuffle=True, pass a random_state integer so that the shuffle is deterministic: KFold(n_splits=5, shuffle=True, random_state=42). Shuffling is recommended when the dataset is sorted by class or time order, as sequential splits would create highly unrepresentative folds. Always document the random state in your experiments for reproducibility.
from sklearn.model_selection import KFold, cross_val_score
from sklearn.tree import DecisionTreeClassifier
from sklearn.datasets import load_iris
import numpy as np
X, y = load_iris(return_X_y=True)
kf = KFold(n_splits=5, shuffle=True, random_state=42)
scores = cross_val_score(DecisionTreeClassifier(random_state=42), X, y, cv=kf)
print('Shuffled 5-fold scores:', np.round(scores, 4))
print('Mean:', round(scores.mean(), 4))Interpreting Mean and Standard Deviation
The mean CV score estimates your model's expected performance on new data. The standard deviation tells you how stable that performance is. A mean of 0.93 with std 0.01 is much more trustworthy than 0.93 with std 0.08. High standard deviation indicates that model performance is sensitive to which examples are in the training set — a sign of either a small dataset, high model variance, or an unrepresentative data split. When comparing two models, the one with lower variance (smaller std) is often preferred even if its mean is slightly lower.
Choosing K: 5-Fold vs 10-Fold vs LOOCV
The choice of k involves a bias-variance trade-off for the CV estimate itself. k=5: each training set is 80% of the data, fast to compute, slightly high bias. k=10: each training set is 90%, better estimate, more computation. Leave-One-Out CV (LOOCV): k=n, nearly unbiased but extremely slow for large datasets and has high variance between folds. The standard recommendation is k=5 or k=10. For very small datasets (<100 examples), LOOCV gives the most data-efficient estimate.
from sklearn.model_selection import cross_val_score, LeaveOneOut
from sklearn.neighbors import KNeighborsClassifier
from sklearn.datasets import load_iris
import numpy as np
X, y = load_iris(return_X_y=True)
knn = KNeighborsClassifier(n_neighbors=5)
for k in [5, 10]:
scores = cross_val_score(knn, X, y, cv=k)
print(f'{k}-fold CV: mean={scores.mean():.4f}, std={scores.std():.4f}')
# LOOCV is slow for large datasets; feasible here
loo_scores = cross_val_score(knn, X, y, cv=LeaveOneOut())
print(f'LOOCV: mean={loo_scores.mean():.4f}, std={loo_scores.std():.4f}')cross_validate: Multiple Metrics at Once
cross_validate is a more powerful variant that can compute multiple metrics simultaneously and also return training scores and fit/score times. This is useful for comparing train vs test scores (to diagnose overfitting) or computing multiple metrics (accuracy, F1, AUC) in a single CV run instead of running CV separately for each metric.
from sklearn.model_selection import cross_validate
from sklearn.ensemble import RandomForestClassifier
from sklearn.datasets import load_breast_cancer
import numpy as np
X, y = load_breast_cancer(return_X_y=True)
rf = RandomForestClassifier(n_estimators=100, random_state=42)
results = cross_validate(rf, X, y, cv=5,
scoring=['accuracy', 'f1', 'roc_auc'],
return_train_score=True)
for metric in ['test_accuracy', 'test_f1', 'test_roc_auc']:
vals = results[metric]
print(f'{metric}: {vals.mean():.4f} (+/- {vals.std():.4f})')When K-Fold CV Can Be Misleading
K-Fold CV gives misleading estimates in several scenarios: (1) Time-series data — shuffling and splitting ignores temporal order, creating leakage where future data trains models used to predict the past; (2) Group data — if multiple rows belong to the same patient or user, splitting them into different folds leaks group-level patterns; (3) Highly imbalanced classes — random splits may put all positive examples in the training set. Use specialised CV variants: TimeSeriesSplit, GroupKFold, and StratifiedKFold for these cases.
Cross-Validation Is Evaluation, Not Training
A common misconception: K-Fold CV does not produce a deployable model. Each of the k model fits is discarded after evaluation. Cross-validation exists solely to estimate how a model trained with your chosen hyperparameters and pipeline will perform on unseen data. Once you are satisfied with the CV estimate, you retrain your final model on the complete training dataset (all folds combined) with those hyperparameters and deploy that model. The CV score is your honest estimate of its expected performance.
Reporting CV Results: Mean and Confidence Interval
When reporting cross-validation results, always report both the mean and the standard deviation: 0.932 ± 0.012. This conveys not just performance but stability. For publication or stakeholder reports, you can also compute a 95% confidence interval: mean ± 1.96 × std / sqrt(k). When comparing two models, check whether their confidence intervals overlap — overlapping intervals suggest the difference is not statistically meaningful and may just reflect random variation in the data split.
from sklearn.ensemble import RandomForestClassifier
from sklearn.datasets import load_breast_cancer
from sklearn.model_selection import cross_val_score
import numpy as np
X, y = load_breast_cancer(return_X_y=True)
scores = cross_val_score(RandomForestClassifier(n_estimators=100, random_state=42), X, y, cv=10)
mean, std = scores.mean(), scores.std()
ci95 = 1.96 * std / np.sqrt(len(scores))
print(f'CV Mean: {mean:.4f}')
print(f'CV Std: {std:.4f}')
print(f'95% CI: [{mean-ci95:.4f}, {mean+ci95:.4f}]')Quick Check
Test your understanding of K-Fold Cross-Validation from this lesson.
Lesson Recap
In this lesson you learned: K-Fold CV estimates generalisation by averaging scores across k non-overlapping test folds, always use a Pipeline to prevent preprocessing from leaking test fold statistics into training, and CV is an evaluation tool — retrain on all data after selecting hyperparameters. Next up we explore Stratified and Time-Series cross-validation for specialised data types.
常见问题解答
「K 折交叉验证:无数据泄漏地划分」课时是免费的吗?
是的 — 「K 折交叉验证:无数据泄漏地划分」的完整文本可在网页上免费阅读。要进行交互式练习(内置代码编辑器和全天候 AI 导师)并解锁 Machine Learning Academy 课程的其余内容,请升级到 CoddyKit PRO。 Machine Learning Academy 课程共包含 4 节课。
「K 折交叉验证:无数据泄漏地划分」这节课中我会学到什么?
您将使用 cross_val_score 实现 5 折 CV,理解为什么测试折在训练期间从未被使用,并解读 CV 分数的均值和标准差。 你通过在浏览器中直接运行的动手代码来练习 Machine Learning Academy,全天候 AI 导师会在你学习这节课的过程中回答你的问题。
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「K 折交叉验证:无数据泄漏地划分」课时需要多长时间?
大多数 CoddyKit 课程大约需要 5–10 分钟。每节课都很精短且互动,所以你能稳步进步,并在网页和应用中从离开的地方继续。
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此课程中的所有课时
- K 折交叉验证:无数据泄漏地划分
- 分层交叉验证与时间序列交叉验证
- 网格搜索与随机搜索
- 嵌套交叉验证:同时进行选择与评估