Django Academy · 课时

Paginator 类

将查询集拆分为多个页面

Paginator 类 是 CoddyKit 上的免费 Django Academy 课时。这是第 1 节课，共 4 节。你可以在下方免费阅读本课时的完整内容 — 然后在浏览器中使用内置代码编辑器和全天候 AI 导师进行实践。这是 Django Academy 学习路径的一部分，你的进度在网页和 CoddyKit 应用中同步。 Django Academy 课程共包含 4 节课。

本课时的部分内容尚未翻译，以英文显示。

Why Paginate?

Showing 5,000 rows on one page is slow and overwhelming. Pagination splits a long list into bite-sized pages your users can browse. 📄

Meet the Paginator

Django ships a Paginator class that does the math for you. You hand it a list and a page size, and it carves the data into pages.

from django.core.paginator import Paginator

Create a Paginator

Pass your full queryset and how many items per page. Here every page holds 10 articles.

articles = Article.objects.all()
paginator = Paginator(articles, 10)

Counting the Pages

Ask the paginator how many pages exist with num_pages. It rounds up, so 25 items at 10 per page gives 3 pages.

paginator.num_pages  # 3

Grab One Page

Call get_page() with a page number to fetch a single slice. It returns a Page object holding just those items.

page = paginator.get_page(2)

Looping Over a Page

A Page is iterable, so you loop it like a list. You only ever touch the items on that one page, never all 5,000.

for article in page:
    print(article.title)

get_page Is Forgiving

If someone passes page 999 or the word "abc", get_page() quietly returns the last or first valid page instead of crashing.

Knowing Where You Are

The page knows its own spot. Read number for the current page, handy for highlighting it in your navigation bar.

page.number  # 2

Next and Previous

Use has_next() and has_previous() to decide whether to show the next or back link in your template.

page.has_next()
page.has_previous()

The Neighboring Pages

Once you know there is a next page, next_page_number() gives you the number to link to. previous_page_number() does the same backward.

page.next_page_number()  # 3

Wiring It Into a View

In a view, read the requested page from the query string, then pass the page to your template context.

num = request.GET.get('page')
page = paginator.get_page(num)

Quick Check

You have 23 items and a page size of 10. Let's test the math.

Recap

You met the Paginator: feed it a queryset and a page size, fetch slices with get_page(), and read num_pages, number, and has_next() to build navigation. 🎉

常见问题解答

「Paginator 类」课时是免费的吗？

是的 — 「Paginator 类」的完整文本可在网页上免费阅读。要进行交互式练习（内置代码编辑器和全天候 AI 导师）并解锁 Django Academy 课程的其余内容，请升级到 CoddyKit PRO。 Django Academy 课程共包含 4 节课。

「Paginator 类」这节课中我会学到什么？

将查询集拆分为多个页面你通过在浏览器中直接运行的动手代码来练习 Django Academy，全天候 AI 导师会在你学习这节课的过程中回答你的问题。

学习 Django Academy 需要有经验吗？

无需任何先前经验。CoddyKit 上的 Django Academy 课程适合初学者到高级学习者，你可以从这里开始或从头开始，按照自己的节奏学习。这是第 1 节课，共 4 节。

「Paginator 类」课时需要多长时间？

大多数 CoddyKit 课程大约需要 5–10 分钟。每节课都很精短且互动，所以你能稳步进步，并在网页和应用中从离开的地方继续。

我能在这节 Django Academy 课中编写并运行代码吗？

能。每节 Django Academy 课都包含内置代码编辑器，你可以在浏览器中直接编写并运行真实代码，并获得即时 AI 反馈 — 无需本地设置。

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