중첩 반복문에서 빠져나오기

for i in 1...3 {
    for j in 1...3 {
        if j == 2 { break }
        print(i, j)
    }
}

outer: for i in 1...3 {
    for j in 1...3 {
        if i == 2 && j == 2 { break outer }
        print(i, j)
    }
}
print("escaped")

let grid = [[1, 2, 3], [4, 5, 6]]
var position = (-1, -1)
find: for r in 0..<grid.count {
    for c in 0..<grid[r].count {
        if grid[r][c] == 5 {
            position = (r, c)
            break find
        }
    }
}
print(position)

var stop = false
for i in 1...3 {
    for j in 1...3 {
        if i + j == 4 { stop = true; break }
        print(i, j)
    }
    if stop { break }
}

outer: for i in 1...3 {
    for j in 1...3 {
        if i + j == 4 { break outer }
        print(i, j)
    }
}

top: for a in 1...2 {
    for b in 1...2 {
        for c in 1...2 {
            if c == 2 { break top }
            print(a, b, c)
        }
    }
}

rows: for r in 1...3 {
    for c in 1...3 {
        if c == 2 { continue rows }
        print(r, c)
    }
}

scan: for i in 1...3 {
    for j in 1...3 {
        if j == 1 { continue }
        if i == 3 { break scan }
        print(i, j)
    }
}

let data = Array(1...100)
var firstBig = -1
loop: for chunk in stride(from: 0, to: data.count, by: 10) {
    for k in chunk..<min(chunk + 10, data.count) {
        if data[k] > 25 {
            firstBig = data[k]
            break loop
        }
    }
}
print(firstBig)

func findPair(_ target: Int) -> (Int, Int)? {
    for i in 1...5 {
        for j in 1...5 {
            if i * j == target { return (i, j) }
        }
    }
    return nil
}
print(findPair(12) ?? (-1, -1))

outer: for x in 1...3 {
    for y in 1...3 {
        if x * y >= 4 { break outer }
        print(x, y)
    }
}

outer: for i in 1...3 {
    for j in 1...3 {
        if j == 2 { break outer }
        print(i, j)
    }
}