कोड के प्रदर्शन को मापना

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    auto start = steady_clock::now();
    long sum = 0;
    for (int i = 0; i < 500000; ++i) sum += i;
    auto end = steady_clock::now();
    auto us = duration_cast<microseconds>(end - start);
    std::cout << "Result: " << sum << ", us non-negative: " << (us.count() >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    auto start = steady_clock::now();
    long sum = 0;
    for (int i = 0; i < 200000; ++i) sum += i % 7;
    auto end = steady_clock::now();
    duration<double> secs = end - start;
    std::cout << "Computed " << sum << ", seconds >= 0: " << (secs.count() >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

long long timeWork() {
    using namespace std::chrono;
    auto s = steady_clock::now();
    long acc = 0;
    for (int i = 0; i < 100000; ++i) acc += i;
    auto e = steady_clock::now();
    return duration_cast<microseconds>(e - s).count();
}

int main() {
    std::cout << "Microseconds non-negative: " << (timeWork() >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    auto s = steady_clock::now();
    volatile long sink = 0;
    for (int i = 0; i < 100000; ++i) sink += i;
    auto e = steady_clock::now();
    std::cout << "Sink used: " << (sink > 0) << ", elapsed >= 0: " << ((e - s).count() >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

long work() {
    long a = 0;
    for (int i = 0; i < 50000; ++i) a += i;
    return a;
}

int main() {
    using namespace std::chrono;
    work();
    auto s = steady_clock::now();
    long r = work();
    auto e = steady_clock::now();
    std::cout << r << " measured, ok: " << ((e - s).count() >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    long long total = 0;
    const int runs = 5;
    for (int r = 0; r < runs; ++r) {
        auto s = steady_clock::now();
        long acc = 0;
        for (int i = 0; i < 100000; ++i) acc += i;
        auto e = steady_clock::now();
        total += duration_cast<microseconds>(e - s).count();
    }
    std::cout << "Average us non-negative: " << ((total / runs) >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>
#include <vector>

int main() {
    using namespace std::chrono;
    std::vector<int> v;
    auto s1 = steady_clock::now();
    for (int i = 0; i < 10000; ++i) v.push_back(i);
    auto e1 = steady_clock::now();
    v.clear();
    v.reserve(10000);
    auto s2 = steady_clock::now();
    for (int i = 0; i < 10000; ++i) v.push_back(i);
    auto e2 = steady_clock::now();
    std::cout << "Both timed: " << (((e1 - s1).count() >= 0) && ((e2 - s2).count() >= 0)) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    auto s = steady_clock::now();
    int x = 1 + 1;
    auto e = steady_clock::now();
    auto ns = duration_cast<nanoseconds>(e - s).count();
    std::cout << "x=" << x << ", tiny work may read low: " << (ns >= 0) << '\n';
    return 0;
}

#include <iostream>
#include <chrono>

int main() {
    using namespace std::chrono;
    auto s = steady_clock::now();
    long acc = 0;
    for (int i = 0; i < 300000; ++i) acc += (i * 3) % 11;
    auto e = steady_clock::now();
    auto ms = duration_cast<milliseconds>(e - s).count();
    std::cout << "acc=" << acc << ", ms >= 0: " << (ms >= 0) << '\n';
    return 0;
}