Requêtes SQL et jointures avancées
Maîtriser les requêtes SQL complexes, notamment les différents types de jointures, les sous-requêtes et les fonctions de fenêtrage, pour récupérer des jeux de données élaborés.
Requêtes SQL et jointures avancées est une leçon Supabase Backend as a Service gratuite sur CoddyKit. Ceci est la leçon 1 sur 3. Tu peux lire la leçon complète ci-dessous gratuitement — puis la pratiquer en direct dans le navigateur avec un éditeur de code intégré et un tuteur IA 24/7. Elle fait partie du parcours d'apprentissage Supabase Backend as a Service, et ta progression se synchronise sur le web et l'application CoddyKit. Le cours Supabase Backend as a Service comprend 3 leçons au total.
Certaines parties de cette leçon n'ont pas encore été traduites et s'affichent en anglais.
Beyond Basic Queries
Welcome to Advanced SQL Queries! So far, you've learned to select, filter, and sort data. But real-world applications often need to combine data from multiple sources or perform complex calculations.
This lesson will equip you with powerful techniques to retrieve sophisticated datasets, making your Supabase applications even smarter.
Joins Recap: Inner Join
Let's quickly refresh our memory on joins. A JOIN combines rows from two or more tables based on a related column between them.
An INNER JOIN returns only the rows where there is a match in both tables. If a row in one table doesn't have a match in the other, it's excluded.
Try running this example to set up our tables and see an INNER JOIN:
CREATE TABLE departments (
department_id INT PRIMARY KEY,
department_name VARCHAR(50) NOT NULL
);
CREATE TABLE employees (
employee_id INT PRIMARY KEY,
first_name VARCHAR(50) NOT NULL,
last_name VARCHAR(50) NOT NULL,
department_id INT REFERENCES departments(department_id)
);
INSERT INTO departments (department_id, department_name) VALUES
(1, 'Sales'),
(2, 'Marketing'),
(3, 'Engineering'),
(4, 'HR');
INSERT INTO employees (employee_id, first_name, last_name, department_id) VALUES
(101, 'Alice', 'Smith', 1),
(102, 'Bob', 'Johnson', 2),
(103, 'Charlie', 'Brown', 1),
(104, 'Diana', 'Prince', 3),
(105, 'Eve', 'Adams', NULL);
SELECT
e.first_name,
e.last_name,
d.department_name
FROM
employees e
INNER JOIN
departments d ON e.department_id = d.department_id;Left Join: All from the Left
What if you want to see all employees, even those not assigned to a department yet? That's where LEFT JOIN (or LEFT OUTER JOIN) comes in handy.
A LEFT JOIN returns all rows from the 'left' table (the first one mentioned) and the matching rows from the 'right' table. If there's no match on the right, NULL values are returned for the right table's columns.
Run this to see employee Eve Adams, who has no department:
SELECT
e.first_name,
e.last_name,
d.department_name
FROM
employees e
LEFT JOIN
departments d ON e.department_id = d.department_id;Right Join: All from the Right
The opposite of a LEFT JOIN is a RIGHT JOIN (or RIGHT OUTER JOIN). It returns all rows from the 'right' table and matching rows from the 'left' table.
If there's no match on the left, NULL values are returned for the left table's columns. This is less common, as you can often rewrite it as a LEFT JOIN by swapping table order.
Let's find all departments, including 'HR' which currently has no employees:
SELECT
e.first_name,
e.last_name,
d.department_name
FROM
employees e
RIGHT JOIN
departments d ON e.department_id = d.department_id;Full Outer Join: Everything!
Want to see everything? A FULL OUTER JOIN (or just FULL JOIN) returns all rows when there is a match in either the left or the right table.
If a row doesn't have a match in the other table, the columns from the non-matching side will have NULL values. It's like combining a LEFT and a RIGHT join.
Observe how both Eve (no department) and HR (no employees) appear:
SELECT
e.first_name,
e.last_name,
d.department_name
FROM
employees e
FULL OUTER JOIN
departments d ON e.department_id = d.department_id;Self Join: Table to Itself
Sometimes, you need to join a table to itself. This is called a SELF JOIN and is useful for finding relationships within the same table, like 'employees and their managers'.
To do this, you use table aliases to treat the same table as two separate entities in your query.
Let's add a manager column and find out who manages whom:
ALTER TABLE employees
ADD COLUMN manager_id INT REFERENCES employees(employee_id);
UPDATE employees SET manager_id = 101 WHERE employee_id = 102;
UPDATE employees SET manager_id = 101 WHERE employee_id = 103;
UPDATE employees SET manager_id = 104 WHERE employee_id = 105;
SELECT
E.first_name AS employee_name,
M.first_name AS manager_name
FROM
employees E
INNER JOIN
employees M ON E.manager_id = M.employee_id;Introducing Subqueries
Beyond joins, subqueries (also called inner queries or nested queries) are another powerful tool. A subquery is simply a SQL query nested inside a larger query.
They can be used to:
- Filter data in a
WHEREclause. - Define columns in a
SELECTclause. - Create derived tables in a
FROMclause.
Subqueries execute first, and their result is then used by the outer query.
Subqueries in WHERE Clause
A common use for subqueries is in the WHERE clause to filter results dynamically. You can use operators like IN, EXISTS, =, <, > with subqueries.
For example, let's find all employees who work in the 'Sales' department without knowing the department_id beforehand:
SELECT
first_name, last_name
FROM
employees
WHERE
department_id IN (
SELECT department_id
FROM departments
WHERE department_name = 'Sales'
);Scalar Subqueries in SELECT
A scalar subquery is a subquery that returns a single value (one row, one column). These are often used in the SELECT clause to add a calculated value to each row of the main query.
Let's find each employee's name and also show the total number of employees in their department. This demonstrates how a subquery can compute a value for each row.
SELECT
e.first_name,
e.last_name,
d.department_name,
(SELECT COUNT(*)
FROM employees
WHERE department_id = e.department_id) AS dept_employee_count
FROM
employees e
LEFT JOIN
departments d ON e.department_id = d.department_id;Advanced Queries Challenge
Consider a scenario where you want to list all departments, and for each department, show the names of employees working there. If a department has no employees, it should still appear in the list with NULL for employee names.
Which SQL JOIN type is most appropriate for this task?
Recap: Your SQL Superpowers
You've gained some serious SQL superpowers today!
- Joins: Beyond INNER JOIN, you learned about LEFT, RIGHT, and FULL OUTER JOINs to handle different data inclusion needs.
- Self Join: How to join a table to itself for hierarchical data.
- Subqueries: Nesting queries to filter data (WHERE clause) or compute scalar values (SELECT clause).
These techniques are fundamental for building powerful and flexible data retrieval logic in your Supabase projects. Keep practicing!
Questions Fréquemment Posées
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Maîtriser les requêtes SQL complexes, notamment les différents types de jointures, les sous-requêtes et les fonctions de fenêtrage, pour récupérer des jeux de données élaborés. Tu pratiques Supabase Backend as a Service avec du code pratique que tu exécutes directement dans le navigateur, et un tuteur IA 24/7 répond à tes questions au fur et à mesure que tu avances dans la leçon.
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Toutes les leçons de ce cours
- Requêtes SQL et jointures avancées
- Indexation des bases de données pour les performances
- Fonctions et déclencheurs de base de données