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Go Academy · Lesson

Buffered Channels

Capacity, closing channels, and range over channel

Buffered Channels is a free Go Academy lesson on CoddyKit — lesson 3 of 4. You can read the complete lesson below for free — then practise it hands-on in the browser with a built-in code editor and a 24/7 AI tutor. It is part of the Go Academy learning path, one of 4 lessons in the course, and your progress syncs across the web and the CoddyKit app.

What Is a Buffered Channel?

A buffered channel has a capacity — sends do not block as long as the buffer has space. The channel acts like a queue:

package main
import "fmt"

func main() {
    ch := make(chan int, 3)  // capacity 3

    ch <- 1  // does not block — buffer has room
    ch <- 2  // does not block
    ch <- 3  // does not block
    // ch <- 4  // would block — buffer full

    fmt.Println(<-ch) // 1
    fmt.Println(<-ch) // 2
    fmt.Println(<-ch) // 3
}

Buffered Channel as Queue

Buffered channels implement a FIFO queue between goroutines:

package main
import ("fmt"; "sync")

func producer(ch chan<- int, wg *sync.WaitGroup) {
    defer wg.Done()
    for i := 1; i <= 5; i++ {
        ch <- i
        fmt.Printf("produced %d\n", i)
    }
}

func main() {
    ch := make(chan int, 2)  // buffer 2 — producer runs ahead
    var wg sync.WaitGroup
    wg.Add(1)
    go producer(ch, &wg)
    wg.Wait()
    close(ch)
    for v := range ch { fmt.Printf("consumed %d\n", v) }
}

len() and cap() on Channels

Inspect a buffered channel's current size and capacity:

package main
import "fmt"

func main() {
    ch := make(chan string, 5)
    ch <- "a"
    ch <- "b"
    ch <- "c"

    fmt.Println("cap:", cap(ch))  // 5
    fmt.Println("len:", len(ch))  // 3 — items currently buffered

    <-ch
    fmt.Println("len:", len(ch))  // 2
}

Decoupling Producer and Consumer

A buffer decouples the producer's speed from the consumer's. The producer can run ahead by buffer size before blocking:

package main
import ("fmt"; "sync"; "time")

func produce(ch chan<- int, wg *sync.WaitGroup) {
    defer wg.Done()
    for i := 0; i < 5; i++ {
        ch <- i
    }
}

func consume(ch <-chan int, wg *sync.WaitGroup) {
    defer wg.Done()
    for v := range ch {
        time.Sleep(10 * time.Millisecond)  // slower consumer
        fmt.Println("consumed:", v)
    }
}

func main() {
    ch := make(chan int, 3)
    var wg sync.WaitGroup
    wg.Add(2)
    go produce(ch, &wg)
    go consume(ch, &wg) // BUG: produce closes before consume sees all
    // In practice, coordinate close carefully
    fmt.Println("decoupled")
}

Semaphore with Buffered Channel

A buffered channel of capacity N can limit concurrent goroutines to N — a simple semaphore:

package main
import ("fmt"; "sync"; "time")

func main() {
    sem := make(chan struct{}, 3)  // max 3 concurrent
    var wg sync.WaitGroup

    for i := 0; i < 10; i++ {
        wg.Add(1)
        i := i
        go func() {
            defer wg.Done()
            sem <- struct{}{}    // acquire
            defer func() { <-sem }()  // release
            fmt.Printf("job %d running\n", i)
            time.Sleep(50 * time.Millisecond)
        }()
    }
    wg.Wait()
}

Closing a Buffered Channel

Closing a buffered channel allows receivers to drain remaining buffered values before detecting closure:

package main
import "fmt"

func main() {
    ch := make(chan int, 5)
    for i := 1; i <= 3; i++ { ch <- i }
    close(ch)

    // Drain all buffered values after close:
    for v := range ch {
        fmt.Println(v)  // 1, 2, 3
    }
    // range exits after channel closed and drained
}

Buffered vs Unbuffered: When to Choose

Decision guide:

  • Unbuffered: guaranteed synchronous handoff, strict ordering, rendezvous synchronization
  • Buffered: decouple producer/consumer speeds, reduce blocking, implement semaphores, collect N results
  • Default to unbuffered — add buffer only when you can justify the size
  • A buffer size that's too small → still blocks; too large → hides bugs

Collecting Results with Buffered Channel

Use a buffered channel to collect results from parallel goroutines without blocking:

package main
import ("fmt"; "sync")

func square(n int) int { return n * n }

func main() {
    nums := []int{1, 2, 3, 4, 5}
    results := make(chan int, len(nums))  // buffer = goroutine count
    var wg sync.WaitGroup

    for _, n := range nums {
        wg.Add(1)
        n := n
        go func() {
            defer wg.Done()
            results <- square(n)
        }()
    }
    wg.Wait()
    close(results)

    for r := range results { fmt.Println(r) }
}

Goroutine Leak with Full Buffer

If the buffer is full and no reader exists, the sender blocks forever — a goroutine leak:

package main
import ("fmt"; "time"; "runtime")

func main() {
    ch := make(chan int, 2)
    // Start goroutine that fills buffer and then blocks
    go func() {
        ch <- 1
        ch <- 2
        ch <- 3  // blocks: buffer full, no receiver
        fmt.Println("never reached")
    }()
    time.Sleep(50 * time.Millisecond)
    fmt.Println("goroutines:", runtime.NumGoroutine()) // 2 — leaked
}

time.After as Buffered Channel

time.After returns a <-chan time.Time buffered with 1. The runtime sends to it after the duration, then it's garbage collected:

package main
import ("fmt"; "time")

func doWithTimeout(work func() string) (string, bool) {
    result := make(chan string, 1)
    go func() { result <- work() }()
    select {
    case r := <-result:
        return r, true
    case <-time.After(100 * time.Millisecond):
        return "", false
    }
}

func main() {
    r, ok := doWithTimeout(func() string {
        time.Sleep(50 * time.Millisecond)
        return "done"
    })
    fmt.Println(r, ok)
}

Quick Check

What happens when you send to a buffered channel that is at full capacity?

Recap: Buffered Channels

Summary:

  • make(chan T, N) creates a buffered channel with capacity N
  • Sends block only when buffer is full; receives block only when empty
  • len(ch) — current items; cap(ch) — capacity
  • Use to decouple producers/consumers, collect parallel results, implement semaphores
  • Close allows drain before EOF; range ch handles this automatically

Frequently asked questions

Is the “Buffered Channels” lesson free?

Yes — the full text of “Buffered Channels” is free to read here on the web, and the Go Academy course includes 4 lessons in total. To practise it interactively (a built-in code editor and a 24/7 AI tutor) and unlock the rest of the Go Academy course, upgrade to CoddyKit PRO.

What will I learn in “Buffered Channels”?

Capacity, closing channels, and range over channel You practise Go Academy with hands-on code you run directly in the browser, and a 24/7 AI tutor answers your questions as you work through the lesson.

Do I need any experience to start Go Academy?

No prior experience is required. Go Academy on CoddyKit is structured for beginners through advanced learners; this is — lesson 3 of 4, so you can start here or from the beginning and move at your own pace.

How long does the “Buffered Channels” lesson take?

Most CoddyKit lessons take about 5–10 minutes. Each one is bite-sized and interactive, so you make steady progress and pick up exactly where you left off across the web and the app.

Can I write and run code in this Go Academy lesson?

Yes. Every Go Academy lesson includes a built-in code editor, so you write and run real code right in your browser and get instant AI feedback — no local setup required.

All lessons in this course

  1. Launching Goroutines
  2. Unbuffered Channels
  3. Buffered Channels
  4. Channel Direction and Pipeline Patterns
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